-11v=2v^2-15

Solution for -11v=2v^2-15 equation:

-11v=2v^2-15

We move all terms to the left:

-11v-(2v^2-15)=0

We get rid of parentheses

-2v^2-11v+15=0

a = -2; b = -11; c = +15;
Δ = b2-4ac
Δ = -112-4·(-2)·15
Δ = 241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{241}}{2*-2}=\frac{11-\sqrt{241}}{-4}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{241}}{2*-2}=\frac{11+\sqrt{241}}{-4}
$